本文整理匯總了PHP中App\Model\User::getRoles方法的典型用法代碼示例。如果您正苦於以下問題：PHP User::getRoles方法的具體用法？PHP User::getRoles怎麽用？PHP User::getRoles使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類App\Model\User的用法示例。
在下文中一共展示了User::getRoles方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: index
/**
* Index action method
*
* @return void
*/
public function index($rid = null)
{
if (null === $rid || $this->services['acl']->isAllowed($this->sess->user->role, 'users-of-role-' . $rid, 'index')) {
$deniedRoles = [];
$resources = $this->services['acl']->getResources();
foreach ($resources as $name => $resource) {
if (!$this->services['acl']->isAllowed($this->sess->user->role, $name, 'index')) {
$deniedRoles[] = (int) substr($name, strrpos($name, '-') + 1);
}
}
$user = new Model\User();
$searchUsername = $this->request->getQuery('search_username');
if ($user->hasPages($this->application->config()['pagination'], $rid, $searchUsername, $deniedRoles)) {
$limit = $this->application->config()['pagination'];
$pages = new Paginator($user->getCount($rid, $searchUsername, $deniedRoles), $limit);
$pages->useInput(true);
} else {
$limit = null;
$pages = null;
}
$this->prepareView('users/index.phtml');
$this->view->title = 'Users';
$this->view->pages = $pages;
$this->view->roleId = $rid;
$this->view->queryString = $this->getQueryString('sort');
$this->view->searchUsername = $searchUsername;
$this->view->users = $user->getAll($rid, $searchUsername, $deniedRoles, $limit, $this->request->getQuery('page'), $this->request->getQuery('sort'));
$this->view->roles = $user->getRoles();
$this->send();
} else {
$this->redirect('/users');
}
}示例2: updateUser
/**
* Sorry this changes will be not persisted.
*
* @param User $user
* @param string $password
*/
public function updateUser(User $user, $password)
{
$this->database[$user->getName()] = ['password' => $this->encode($password), 'roles' => $user->getRoles()];
}