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PHP City::paginate方法代碼示例

本文整理匯總了PHP中app\City::paginate方法的典型用法代碼示例。如果您正苦於以下問題:PHP City::paginate方法的具體用法?PHP City::paginate怎麽用?PHP City::paginate使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在app\City的用法示例。


在下文中一共展示了City::paginate方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: index

 /**
  * Display a listing of the resource.
  *
  * @return \Illuminate\Http\Response
  */
 public function index(Request $request)
 {
     $this->validate($request, ['search' => 'string|max:20', 'country_id' => 'integer|exists:country,id']);
     if ($request->has('search') && $request->has('country_id')) {
         $search = $request->input('search');
         $cities = City::whereHas('translations', function ($query) use($search) {
             $query->where('name', 'like', $search . '%');
         })->where('country_id', $request->input('country_id'))->paginate(15);
     } elseif ($request->has('search')) {
         $search = $request->input('search');
         $cities = City::whereHas('translations', function ($query) use($search) {
             $query->where('name', 'like', $search . '%');
         })->paginate(15);
     } elseif ($request->has('country_id')) {
         $cities = City::where('country_id', $request->input('country_id'))->paginate(15);
     } else {
         $cities = City::paginate(15);
     }
     if ($request->wantsJSON()) {
         return response()->json($cities->toArray(), 200);
     } else {
         return view('pages.city.index', ['cities' => $cities]);
     }
 }
開發者ID:santakani,項目名稱:santakani.com,代碼行數:29,代碼來源:CityController.php

示例2: index

 /**
  * Display a listing of the resource.
  *
  * @return Response
  */
 public function index()
 {
     $city = City::paginate();
     return view('settings.citys.index', compact('city'));
 }
開發者ID:raulbravo23,項目名稱:salepoint,代碼行數:10,代碼來源:CitysController.php


注:本文中的app\City::paginate方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。