本文整理匯總了PHP中response::getDiseasetype方法的典型用法代碼示例。如果您正苦於以下問題：PHP response::getDiseasetype方法的具體用法？PHP response::getDiseasetype怎麽用？PHP response::getDiseasetype使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類response的用法示例。
在下文中一共展示了response::getDiseasetype方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: getCode
class error
{
public $code = "";
public function getCode()
{
return $this->code;
}
}
$output = new response();
$err = new error();
//SQL query goes here
//Location is default to "BC", Days is defaulted to 5,
//Desease is defauled to 'flu'
$output->diseasetype = "flu";
$output->location = "BC";
$sql = "SELECT infected FROM " . $output->getLocation() . " WHERE deseasetype = '" . $output->getDiseasetype() . "' LIMIT 5";
$result = $conn->query($sql);
//JSON parsing and echo go here
if ($result->num_rows == 5) {
while ($r = $result->fetch_assoc()) {
$output->arrayInfected[] = $r;
}
echo json_encode($output);
} else {
$err->code = "Something went wrong";
echo json_encode($err);
}
$conn->close;
?>