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PHP UserStatus::create方法代碼示例

本文整理匯總了PHP中UserStatus::create方法的典型用法代碼示例。如果您正苦於以下問題:PHP UserStatus::create方法的具體用法?PHP UserStatus::create怎麽用?PHP UserStatus::create使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在UserStatus的用法示例。


在下文中一共展示了UserStatus::create方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: testBelongTo

 public function testBelongTo()
 {
     $this->createPostsWithComments(5, 10);
     $this->assertEqual(BlogPost::count(), 5);
     $this->assertEqual(BlogComment::count(), 50);
     $comment = BlogComment::findFirst(['conditions' => 'title = ?', 'values' => ['Comment 4 to Post 3']]);
     $this->assertEqual($comment->message, 'This is a comment message 3:4!');
     // Test belongsTo collection
     $queryCount = TipyDAO::$queryCount;
     $post = $comment->post;
     // We got a new query
     $this->assertEqual(TipyDAO::$queryCount, $queryCount + 1);
     $this->assertNotEqual($post, null);
     $this->assertEqual($post->title, 'Post 3');
     // Test cached association
     $this->assertNotEqual($comment->associationsCache["post"], null);
     $this->assertEqual($post, $comment->associationsCache["post"]);
     // Test no query
     $queryCount = TipyDAO::$queryCount;
     $postAgain = $comment->post;
     // no more queries
     $this->assertEqual(TipyDAO::$queryCount, $queryCount);
     $this->assertEqual($post, $postAgain);
     // belongsTo crash
     $status = UserStatus::create(['name' => 'Some status']);
     $user = User::create(['login' => 'login', 'password' => 'password', 'email' => 'email@example.com', 'userStatusId' => $status->id]);
     $this->assertEqual($user->userStatus->name, 'Some status');
 }
開發者ID:smetana,項目名稱:tipy,代碼行數:28,代碼來源:AssociationsTest.php


注:本文中的UserStatus::create方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。