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PHP UserDAO::getUsersByRoleID方法代碼示例

本文整理匯總了PHP中UserDAO::getUsersByRoleID方法的典型用法代碼示例。如果您正苦於以下問題:PHP UserDAO::getUsersByRoleID方法的具體用法?PHP UserDAO::getUsersByRoleID怎麽用?PHP UserDAO::getUsersByRoleID使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在UserDAO的用法示例。


在下文中一共展示了UserDAO::getUsersByRoleID方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: displayUser

function displayUser($user, $tpl)
{
    $tpl->define(array("user" => "settings/user.html", "user_tr" => "settings/user_tr.html", "user_role" => "settings/user_role.html", "user_root" => "settings/user_root.html"));
    $roleID = $user->getRole()->getRoleID();
    $userDAO = new UserDAO();
    if ($roleID === "1") {
        $tpl->parse("SETTINGS_USER_TD_ROOT", "user_root");
        $roleUsers1 = $userDAO->getUsersByRoleID("1");
        changRole($tpl, $roleUsers1, "1");
        $roleUsers2 = $userDAO->getUsersByRoleID("2");
        changRole($tpl, $roleUsers2, "2");
        $roleUsers3 = $userDAO->getUsersByRoleID("3");
        changRole($tpl, $roleUsers3, "3");
        $roleUsers4 = $userDAO->getUsersByRoleID("4");
        changRole($tpl, $roleUsers4, "4");
    } elseif ($roleID === "2") {
        $tpl->assign("SETTINGS_USER_TD_ROOT", "");
        $roleUsers3 = $userDAO->getUsersByRoleID("3");
        if ($roleUsers3 === null) {
            $tpl->assign("SETTINGS_USER_TR", "");
        }
        changRole($tpl, $roleUsers3, "3");
        $roleUsers4 = $userDAO->getUsersByRoleID("4");
        if ($roleUsers4 === null) {
            $tpl->assign("SETTINGS_USER_TR", "");
        }
        changRole($tpl, $roleUsers4, "4");
    } elseif ($roleID === "3" || $roleID === "4") {
        $tpl->assign("SETTINGS_USER_TR", "");
    }
    $tpl->parse("SETTINGS_USER", "user");
}
開發者ID:hstonec,項目名稱:discussion,代碼行數:32,代碼來源:settings.php


注:本文中的UserDAO::getUsersByRoleID方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。