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PHP UserClass::LoggedIn方法代碼示例

本文整理匯總了PHP中UserClass::LoggedIn方法的典型用法代碼示例。如果您正苦於以下問題:PHP UserClass::LoggedIn方法的具體用法?PHP UserClass::LoggedIn怎麽用?PHP UserClass::LoggedIn使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在UserClass的用法示例。


在下文中一共展示了UserClass::LoggedIn方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: UserClass

<?php

ob_start();
include "UserClass.php";
$USER = new UserClass();
if ($USER->LoggedIn()) {
    // Tacos
} else {
    header("Location: http://linux4hope.org/404");
}
require "dbclass.php";
$dbobj = new dbclass();
$cxn = $dbobj->cxn;
$appid = mysqli_real_escape_string($cxn, $_GET['id']);
$action = mysqli_real_escape_string($cxn, $_GET['action']);
if ($action === "approve") {
    //Set approved, undelivered
    $result = mysqli_query($cxn, "Select * from PENDING_APPS where APP_ID = {$appid}");
    $row = mysqli_fetch_assoc($result);
    if (!empty($row)) {
        extract($row);
        $remove = "Delete from PENDING_APPS where APP_ID = {$appid}";
        $add = "Insert into ACCEPTED_APPS(APP_ID,APPLICANT_ID) values({$appid},{$APPLICANT_ID})";
        mysqli_query($cxn, $remove) or die("Couldn't remove pending app");
        mysqli_query($cxn, $add) or die("Couldn't add to approved");
        header("Location: https://linux4hope.org/backend/viewapplication?appid={$appid}");
    } else {
        //If no results were found redirect to an error?
    }
} else {
    if ($action === "deny") {
開發者ID:binbot,項目名稱:l4h,代碼行數:31,代碼來源:manageapp.php


注:本文中的UserClass::LoggedIn方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。