本文整理匯總了PHP中Scalr_Account_User::isInTeam方法的典型用法代碼示例。如果您正苦於以下問題：PHP Scalr_Account_User::isInTeam方法的具體用法？PHP Scalr_Account_User::isInTeam怎麽用？PHP Scalr_Account_User::isInTeam使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Scalr_Account_User的用法示例。
在下文中一共展示了Scalr_Account_User::isInTeam方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: isFarmAllowed
/**
* @param DBFarm $dbFarm
* @param string $permissionId
* @return bool
*/
protected function isFarmAllowed(DBFarm $dbFarm = null, $permissionId = null)
{
$acl = \Scalr::getContainer()->acl;
if (is_null($dbFarm)) {
return $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_FARMS, $permissionId) || $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_TEAM_FARMS, $permissionId) || $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_OWN_FARMS, $permissionId);
} else {
if (!$dbFarm instanceof DBFarm) {
throw new \InvalidArgumentException(sprintf('First argument should be instance of DBFarm or null'));
}
$result = $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_FARMS, $permissionId);
if (!$result && $dbFarm->teamId && $this->user->isInTeam($dbFarm->teamId)) {
$result = $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_TEAM_FARMS, $permissionId);
}
if (!$result && $dbFarm->createdByUserId && $this->user->id == $dbFarm->createdByUserId) {
$result = $acl->isUserAllowedByEnvironment($this->user, $this->Environment, \Scalr\Acl\Acl::RESOURCE_OWN_FARMS, $permissionId);
}
return $result;
}
}