本文整理匯總了PHP中Reference::getTableForeignColumnName方法的典型用法代碼示例。如果您正苦於以下問題：PHP Reference::getTableForeignColumnName方法的具體用法？PHP Reference::getTableForeignColumnName怎麽用？PHP Reference::getTableForeignColumnName使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Reference的用法示例。
在下文中一共展示了Reference::getTableForeignColumnName方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: testGetTableForeignColumnName
public function testGetTableForeignColumnName()
{
$expected = 'film_id';
$tableName = 'film';
$row = $this->getMockBuilder(Row::class)->disableOriginalConstructor()->getMock();
$row->expects($this->once())->method('getTableName')->will($this->returnValue($tableName));
$table = $this->getMockBuilder(Table::class)->disableOriginalConstructor()->getMock();
$table->expects($this->once())->method('getForeignKey')->with($this->equalTo($tableName))->will($this->returnValue($expected));
$reference = new Reference($row, $table);
$this->assertEquals($expected, $reference->getTableForeignColumnName(null));
$expected = 'parent_id';
$this->assertEquals($expected, $reference->getTableForeignColumnName($expected));
}