本文整理匯總了PHP中ProjectManager::getPaginatedResults方法的典型用法代碼示例。如果您正苦於以下問題：PHP ProjectManager::getPaginatedResults方法的具體用法？PHP ProjectManager::getPaginatedResults怎麽用？PHP ProjectManager::getPaginatedResults使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類ProjectManager的用法示例。
在下文中一共展示了ProjectManager::getPaginatedResults方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: ceil
$totalPages = ceil($totalNumberProjects / $itemPerPage);
//fetch position of record
$pagePosition = ($pageNumber - 1) * $itemPerPage;
//fetch paginated results
for ($i = $pagePosition; $i < min($pagePosition + $itemPerPage, $totalNumberProjects); $i++) {
array_push($results, $filteredProjects[$i]);
}
} else {
//get total number of records from database
$totalNumberProjects = $projectMgr->getTotalNumberOfProjects();
//break records into pages
$totalPages = ceil($totalNumberProjects / $itemPerPage);
//fetch position of record
$pagePosition = ($pageNumber - 1) * $itemPerPage;
//Fetch part of records using SQL LIMIT clause
$results = $projectMgr->getPaginatedResults($pagePosition, $itemPerPage);
}
//Display fetched records
if (!empty($results)) {
//$_SESSION['results'] = $filteredProjects;
?>
<div id='thumbnails' class='col-md-10'>
<?php
foreach ($results as $eachProject) {
$project_name = $eachProject["project_name"];
$project_id = $eachProject["project_id"];
$displayURL = $photoMgr->getProjectDisplay($project_id);
?>
<div class='col-md-2 project' style='height:200px;'>
<?php
if (isset($displayURL)) {