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PHP Picture::getPictureById方法代碼示例

本文整理匯總了PHP中Picture::getPictureById方法的典型用法代碼示例。如果您正苦於以下問題:PHP Picture::getPictureById方法的具體用法?PHP Picture::getPictureById怎麽用?PHP Picture::getPictureById使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Picture的用法示例。


在下文中一共展示了Picture::getPictureById方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: Database

<?php

include 'includes/header.php';
$id = $_GET['id'];
$db = new Database();
$pi = new Picture();
$ca = new Category();
$image = $db->select($pi->getPictureById($id))->fetch_assoc();
$categories = $db->select($ca->getAllCategories());
// if submit button is pressed
if (isset($_POST['submit'])) {
    //assign story variables
    $category = mysqli_real_escape_string($db->link, $_POST['category']);
    $title = mysqli_real_escape_string($db->link, $_POST['title']);
    $description = mysqli_real_escape_string($db->link, $_POST['description']);
    $year = mysqli_real_escape_string($db->link, $_POST['year']);
    // simple validation
    if ($title == '' || $description == '' || $category == '' || $year == '') {
        // set error
        $error = 'Please fill out all required fields.';
    } else {
        $update_row = $db->update($pi->updatePicture($category, $year, $title, $description, $id));
    }
}
if (isset($_POST['delete'])) {
    $delete_row = $db->delete($pi->deletePicture($id));
    $filename = "../images/gallery/" . $image['ImagePath'];
    unlink($filename);
}
?>
開發者ID:Owlnofeathers,項目名稱:hansennorthforkranch.ajamesb.com,代碼行數:30,代碼來源:edit_image.php


注:本文中的Picture::getPictureById方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。