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PHP Paginate::has_previous方法代碼示例

本文整理匯總了PHP中Paginate::has_previous方法的典型用法代碼示例。如果您正苦於以下問題:PHP Paginate::has_previous方法的具體用法?PHP Paginate::has_previous怎麽用?PHP Paginate::has_previous使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Paginate的用法示例。


在下文中一共展示了Paginate::has_previous方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1:

    <div class="col-md-8 col-md-offset-3">
    <ul class="pager">

        <?php 
if ($paginate->page_total() > 1) {
    if ($paginate->has_next()) {
        echo "<li class='next'><a href='index.php?page={$paginate->next()}'>Next</a></li>";
    }
    for ($i = 1; $i <= $paginate->page_total(); $i++) {
        if ($i == $paginate->current_page) {
            echo "<li class='active'><a href='index.php?page={$i}'>{$i}</a></li>";
        } else {
            echo "<li class=''><a href='index.php?page={$i}'>{$i}</a></li>";
        }
    }
    if ($paginate->has_previous()) {
        echo " <li class='previous'><a href='index.php?page={$paginate->previous()}'>Previous</a></li>";
    }
}
?>

        
    </ul>

</div>
</div>


            </div>
                </div>
開發者ID:kamy333,項目名稱:rajah,代碼行數:30,代碼來源:photo_gallery.php

示例2: Paginate

<?php 
$page = !empty($_GET['page']) ? $_GET['page'] : 1;
$items_per_page = 10;
$items_total_count = Photo::count_all();
$paginate = new Paginate($page, $items_per_page, $items_total_count);
$sql = "SELECT * FROM photos LIMIT {$paginate->items_per_page} OFFSET {$paginate->offset()}";
$photos = Photo::find_by_query($sql);
?>
        <div class="row">
            <!-- Blog Entries Column -->
            <div class="col-xs-12">
                <nav class="pull-right">
                  <ul class="pagination">
                    <li>
                      <a href="<?php 
echo $paginate->has_previous() ? 'index.php?page=' . $paginate->previous() : '#';
?>
" aria-label="Previous">
                        <span aria-hidden="true">&laquo;</span>
                      </a>
                    </li>
                    <?php 
for ($i = 1; $i <= $paginate->page_total(); $i++) {
    ?>
                        <?php 
    if ($paginate->current_page == $i) {
        ?>
                            <li class="active"><a href="index.php?page=<?php 
        echo $i;
        ?>
"><?php 
開發者ID:amirus2303,項目名稱:gallery,代碼行數:31,代碼來源:index.php


注:本文中的Paginate::has_previous方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。