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PHP ModelCriteria::addJoinObject方法代碼示例

本文整理匯總了PHP中ModelCriteria::addJoinObject方法的典型用法代碼示例。如果您正苦於以下問題:PHP ModelCriteria::addJoinObject方法的具體用法?PHP ModelCriteria::addJoinObject怎麽用?PHP ModelCriteria::addJoinObject使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在ModelCriteria的用法示例。


在下文中一共展示了ModelCriteria::addJoinObject方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: create

 public static function create(\ModelCriteria $q, $relation, $relationAlias = null, $joinType = \Criteria::INNER_JOIN)
 {
     $tableMap = $q->getTableMap();
     $relationMap = $tableMap->getRelation($relation);
     // create a Join object for this join
     $join = new static();
     $join->setJoinType($joinType);
     $join->setRelationMap($relationMap, $q->getModelAlias(), $relationAlias);
     if ($previousJoin = $q->getPreviousJoin()) {
         $join->setPreviousJoin($previousJoin);
     }
     // add the ModelJoin to the current object
     if ($relationAlias) {
         $q->addAlias($relationAlias, $relationMap->getRightTable()->getName());
         $q->addJoinObject($join, $relationAlias);
     } else {
         $q->addJoinObject($join, $relationMap->getRightTable()->getName());
     }
     return $join;
 }
開發者ID:karser,項目名稱:GlorpenPropelBundle,代碼行數:20,代碼來源:PlainModelJoin.php

示例2: testJoinDuplicate

 public function testJoinDuplicate()
 {
     $c = new ModelCriteria('bookstore', 'Author');
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2', 'LEFT JOIN'));
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2', 'LEFT JOIN'));
     $this->assertEquals(1, count($c->getJoins()), 'Expected not to have duplicate LEFT JOIN added.');
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2', 'RIGHT JOIN'));
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2', 'RIGHT JOIN'));
     $this->assertEquals(2, count($c->getJoins()), 'Expected 1 new right join to be added.');
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2'));
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2'));
     $this->assertEquals(3, count($c->getJoins()), 'Expected 1 new implicit join to be added.');
     $c->addJoinObject(new Join('tbl.COL1', 'tbl.COL2', 'INNER JOIN'));
     $this->assertEquals(3, count($c->getJoins()), 'Expected to not add any new join
                                                     as INNER JOIN is default joinType and it is already added');
     $c->addJoinObject(new Join('tbl.COL3', 'tbl.COL4'));
     $this->assertEquals(4, count($c->getJoins()), "Expected new col join to be added.");
 }
開發者ID:kalaspuffar,項目名稱:php-orm-benchmark,代碼行數:18,代碼來源:ModelCriteriaTest.php


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