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PHP JDatabaseQuery::having方法代碼示例

本文整理匯總了PHP中JDatabaseQuery::having方法的典型用法代碼示例。如果您正苦於以下問題:PHP JDatabaseQuery::having方法的具體用法?PHP JDatabaseQuery::having怎麽用?PHP JDatabaseQuery::having使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在JDatabaseQuery的用法示例。


在下文中一共展示了JDatabaseQuery::having方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: testHaving

	/**
	 * Tests the JDatabaseQuery::having method.
	 *
	 * @return  void
	 *
	 * @covers  JDatabaseQuery::having
	 * @since   11.3
	 */
	public function testHaving()
	{
		$this->assertThat(
			$this->_instance->having('COUNT(foo) > 1'),
			$this->identicalTo($this->_instance),
			'Tests chaining.'
		);

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1'),
			'Tests rendered value.'
		);

		// Add another column.
		$this->_instance->having('COUNT(bar) > 2');

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1 AND COUNT(bar) > 2'),
			'Tests rendered value after second use.'
		);

		// Reset the field to test the glue.
		$this->_instance->having = null;
		$this->_instance->having('COUNT(foo) > 1', 'OR');
		$this->_instance->having('COUNT(bar) > 2');

		$this->assertThat(
			trim($this->_instance->having),
			$this->equalTo('HAVING COUNT(foo) > 1 OR COUNT(bar) > 2'),
			'Tests rendered value with OR glue.'
		);
	}
開發者ID:realityking,項目名稱:joomla-platform,代碼行數:42,代碼來源:JDatabaseQueryTest.php


注:本文中的JDatabaseQuery::having方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。