本文整理匯總了PHP中JComments::getCommentsReportForm方法的典型用法代碼示例。如果您正苦於以下問題：PHP JComments::getCommentsReportForm方法的具體用法？PHP JComments::getCommentsReportForm怎麽用？PHP JComments::getCommentsReportForm使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類JComments的用法示例。
在下文中一共展示了JComments::getCommentsReportForm方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: showReportForm
function showReportForm($id, $target)
{
if (JCommentsSecurity::badRequest() == 1) {
JCommentsSecurity::notAuth();
}
$response =& JCommentsFactory::getAjaxResponse();
$db =& JCommentsFactory::getDBO();
$comment = new JCommentsDB($db);
if ($comment->load($id)) {
$form = JComments::getCommentsReportForm($id, $comment->object_id, $comment->object_group);
$response->addAssign($target, 'innerHTML', $form);
}
return $response;
}示例2: showReportForm
public static function showReportForm($id, $target)
{
if (JCommentsSecurity::badRequest() == 1) {
JCommentsSecurity::notAuth();
}
$config = JCommentsFactory::getConfig();
if ($config->getInt('report_reason_required') == 0) {
$_POST['commentid'] = (int) $id;
$response = JCommentsFactory::getAjaxResponse();
$response->addAssign($target, 'innerHTML', '<div id="comments-report-form"></div>');
return self::reportComment();
} else {
$response = JCommentsFactory::getAjaxResponse();
$db = JCommentsFactory::getDBO();
$comment = new JCommentsTableComment($db);
if ($comment->load($id)) {
$form = JComments::getCommentsReportForm($id, $comment->object_id, $comment->object_group);
$response->addAssign($target, 'innerHTML', $form);
}
return $response;
}
}