本文整理匯總了PHP中EfrontLesson::appendTableFiltersUserConstraints方法的典型用法代碼示例。如果您正苦於以下問題：PHP EfrontLesson::appendTableFiltersUserConstraints方法的具體用法？PHP EfrontLesson::appendTableFiltersUserConstraints怎麽用？PHP EfrontLesson::appendTableFiltersUserConstraints使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類EfrontLesson的用法示例。
在下文中一共展示了EfrontLesson::appendTableFiltersUserConstraints方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: countLessonUsers
/**
* Count lesson users based on the specified constraints
* @param array $constraints The constraints for the query
* @return array An array of EfrontUser objects
* @since 3.6.3
* @access public
*/
public function countLessonUsers($constraints = array())
{
!empty($constraints) or $constraints = array('archive' => false, 'active' => true);
list($where, $limit, $orderby) = EfrontUser::convertUserConstraintsToSqlParameters($constraints);
$where[] = "u.login=ul.users_LOGIN and ul.lessons_ID='" . $this->lesson['id'] . "' and ul.archive=0";
$from = EfrontLesson::appendTableFiltersUserConstraints("users u JOIN users_to_lessons ul ON u.login=ul.users_LOGIN", $constraints);
$result = eF_countTableData($from, "distinct(u.login)", implode(" and ", $where));
return $result[0]['count'];
}