本文整理匯總了PHP中Doctrine_Query::getCountSqlQuery方法的典型用法代碼示例。如果您正苦於以下問題：PHP Doctrine_Query::getCountSqlQuery方法的具體用法？PHP Doctrine_Query::getCountSqlQuery怎麽用？PHP Doctrine_Query::getCountSqlQuery使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Doctrine_Query的用法示例。
在下文中一共展示了Doctrine_Query::getCountSqlQuery方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: testCountQuerySupportsIdentifierQuoting
public function testCountQuerySupportsIdentifierQuoting()
{
$q = new Doctrine_Query();
$q->parseDqlQuery('SELECT u.name FROM User u INNER JOIN u.Phonenumber p');
$this->assertEqual($q->getCountSqlQuery(), 'SELECT COUNT(*) AS "num_results" FROM (SELECT "e"."id" FROM "entity" "e" INNER JOIN "phonenumber" "p" ON "e"."id" = "p"."entity_id" WHERE ("e"."type" = 0) GROUP BY "e"."id") "dctrn_count_query"');
}示例2: testAggregateFunctionsInOrderByAndHavingWithCount
public function testAggregateFunctionsInOrderByAndHavingWithCount()
{
$q = new Doctrine_Query();
$q->select('u.*, COUNT(a.id) num_albums')->from('User u')->leftJoin('u.Album a')->orderby('num_albums desc')->groupby('u.id')->having('num_albums > 0')->limit(5);
try {
$this->assertEqual($q->getCountSqlQuery(), 'SELECT COUNT(*) AS num_results FROM (SELECT e.id, COUNT(a.id) AS a__0 FROM entity e LEFT JOIN album a ON e.id = a.user_id WHERE e.type = 0 GROUP BY e.id HAVING a__0 > 0) dctrn_count_query');
$q->count();
$this->pass();
} catch (Doctrine_Exception $e) {
$this->fail($e->getMessage());
}
}