本文整理匯總了PHP中DbConn::executeUpdate方法的典型用法代碼示例。如果您正苦於以下問題：PHP DbConn::executeUpdate方法的具體用法？PHP DbConn::executeUpdate怎麽用？PHP DbConn::executeUpdate使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類DbConn的用法示例。
在下文中一共展示了DbConn::executeUpdate方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: addReviews
public static function addReviews($articleId, $userName, $body, $face)
{
$sql = "insert into reviews(articleId,userName,body,face)values({$articleId},'{$userName}','{$body}','{$face}')";
$conn = new DbConn();
$row = $conn->executeUpdate($sql);
$conn->close();
return $row;
}示例2: addNews
public static function addNews($content, $title, $typeId, $userName, $writer, $source, $imagepath)
{
$sql = "insert into newsArticles(content,title,typeId,userName,writer,source,imagepath)values('{$content}','{$title}',{$typeId},'{$userName}','{$writer}','{$source}','{$imagepath}')";
$conn = new DbConn();
$result = $conn->executeUpdate("update newsTypes set articleNums=articleNums+1 where typeId={$typeId}");
$result = $conn->executeUpdate($sql);
$conn->close();
return $result;
}示例3: addType
public static function addType($typeName)
{
$sql = "insert into newsTypes(typeName)values('{$typeName}')";
$conn = new DbConn();
$result = $conn->executeUpdate($sql);
$conn->close();
return $result;
}