本文整理匯總了PHP中DateTimeUtils::timeFromNow方法的典型用法代碼示例。如果您正苦於以下問題：PHP DateTimeUtils::timeFromNow方法的具體用法？PHP DateTimeUtils::timeFromNow怎麽用？PHP DateTimeUtils::timeFromNow使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類DateTimeUtils的用法示例。
在下文中一共展示了DateTimeUtils::timeFromNow方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: isLeapYear
<?php
DateTimeUtils::addDate('2012-12-01', 1, 'y');
DateTimeUtils::getWeekDay('2012/10/01', '/');
DateTimeUtils::isLeapYear('2012');
DateTimeUtils::timeFromNow(strtotime("2012-10-26 14:15:13"));
class DateTimeUtils
{
/**
* Checks for leap year, returns true if it is. No 2-digit year check. Also
* handles julian calendar correctly.
* @param integer $year year to check
* @return boolean true if is leap year
*/
public static function isLeapYear($year)
{
$year = self::digitCheck($year);
if ($year % 4 != 0) {
return false;
}
if ($year % 400 == 0) {
return true;
} else {
if ($year > 1582 && $year % 100 == 0) {
return false;
}
}
return true;
}
/**
* Fix 2-digit years. Works for any century.
* Assumes that if 2-digit is more than 30 years in future, then previous century.