本文整理匯總了PHP中DatabaseManager::getUserByDisplayName方法的典型用法代碼示例。如果您正苦於以下問題：PHP DatabaseManager::getUserByDisplayName方法的具體用法？PHP DatabaseManager::getUserByDisplayName怎麽用？PHP DatabaseManager::getUserByDisplayName使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類DatabaseManager的用法示例。
在下文中一共展示了DatabaseManager::getUserByDisplayName方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: DatabaseManager
<?php
require_once '../autoload.php';
$user = Auth::user();
$dbManager = new DatabaseManager();
if ($dbManager->isOwner($user, $_GET['scope'])) {
$new_user = $dbManager->getUserByDisplayName($_GET['target']);
if ($new_user) {
json_p(["success" => false, "reason" => "New target owner not found."]);
}
$dbManager->setOwner($new_user, $_GET['scope']);
json_p(["success" => true]);
} else {
json_p(["success" => false, "reason" => "You are not the owner of this room."]);
}示例2:
json_p(['success' => false, 'reason' => "You must be the room owner to make changes to the room password."]);
}
json_p($dbManager->setRoomPassword($scope, $_GET['password']));
break;
case "remove_password":
if (!$dbManager->isOwner($user, $scope)) {
json_p(['success' => false, 'reason' => "You must be the room owner to make changes to the room password."]);
}
json_p($dbManager->removeRoomPassword($scope));
break;
case "transfer_ownership":
if (!$dbManager->isOwner($user, $scope)) {
json_p(['success' => false, 'reason' => "You must be the room owner to transfer room ownership."]);
}
if ($dbManager->checkUser($target)) {
$target_obj = $dbManager->getUserByDisplayName($target);
if ($target_obj) {
json_p($dbManager->setOwner($target_obj->id(), $scope));
} else {
json_p(['success' => false, 'reason' => 'The user you want to transfer to does not exist.']);
}
} else {
json_p(['success' => false, 'reason' => 'Invalid transfer target.']);
}
break;
case "delete":
if (!$dbManager->isOwner($user, $scope)) {
json_p(['success' => false, 'reason' => "You must be the room owner to delete the room."]);
}
json_p($dbManager->deleteRoom($scope));
break;