本文整理匯總了PHP中DataProvider::getPhotostream方法的典型用法代碼示例。如果您正苦於以下問題：PHP DataProvider::getPhotostream方法的具體用法？PHP DataProvider::getPhotostream怎麽用？PHP DataProvider::getPhotostream使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類DataProvider的用法示例。
在下文中一共展示了DataProvider::getPhotostream方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: getAlbumIdByName
$albums = $dataProvider->getPublicAlbums();
$albumId = getAlbumIdByName($albums, $_GET['album']);
if (empty($albumId)) {
die('Could not find a public album with title: ' . $_GET['album'] . '. Please make sure that this album exists and that it is public!');
}
$photos = $dataProvider->getPhotosByAlbum($albumId);
if (!empty($_GET['format']) && $_GET['format'] === "json") {
# Generate RSS as JSON
echo $jsonGenerator->buildJsonFeedForAlbum($_GET['album'], $photos);
} else {
# Generate RSS
echo $rssGenerator->buildRssFeedForAlbum($_GET['album'], $photos);
}
} else {
# Get latest photos
$photos = $dataProvider->getPhotostream();
if (!empty($_GET['format']) && $_GET['format'] === "json") {
# Generate RSS as JSON
echo $jsonGenerator->buildJsonFeedLatestPhotos($photos);
} else {
# Generate RSS
echo $rssGenerator->buildRssFeedLatestPhotos($photos);
}
}
function getAlbumIdByName($albums, $name)
{
foreach ($albums['albums'] as $album) {
if (strtolower($album['title']) === strtolower($name)) {
return $album['id'];
}
}