本文整理匯總了PHP中DataFilter::toSQLDateTime方法的典型用法代碼示例。如果您正苦於以下問題：PHP DataFilter::toSQLDateTime方法的具體用法？PHP DataFilter::toSQLDateTime怎麽用？PHP DataFilter::toSQLDateTime使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類DataFilter的用法示例。
在下文中一共展示了DataFilter::toSQLDateTime方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: actionLogin
/**
* Displays the login page
*/
public function actionLogin()
{
if (!Yii::app()->user->isGuest) {
$this->redirect(Yii::app()->user->returnUrl);
}
$model = new LoginForm();
// if it is ajax validation request
if (isset($_POST['ajax']) && $_POST['ajax'] === 'login-form') {
echo CActiveForm::validate($model);
Yii::app()->end();
}
if (isset($_GET['redir'])) {
Yii::app()->user->returnUrl = $_GET['redir'];
}
// collect user input data
if (isset($_POST['LoginForm'])) {
$model->attributes = $_POST['LoginForm'];
// validate user input and redirect to the previous page if valid
if ($model->validate() && $model->login()) {
## update last_login user
Yii::app()->db->commandBuilder->createUpdateCommand("p_user", ['last_login' => DataFilter::toSQLDateTime(date("Y-m-d H:i:s"))], new CDbCriteria(['condition' => '"id" = :p', 'params' => [':p' => Yii::app()->user->id]]));
## audit trail tracker
AuditTrail::login();
$this->redirect(Yii::app()->user->returnUrl);
}
}
// display the login form
$this->renderForm('LoginForm', $model, [], ['pageTitle' => Setting::get("app.name") . " Login"]);
}