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PHP DAO::findByQueryWithMetaFields方法代碼示例

本文整理匯總了PHP中DAO::findByQueryWithMetaFields方法的典型用法代碼示例。如果您正苦於以下問題:PHP DAO::findByQueryWithMetaFields方法的具體用法?PHP DAO::findByQueryWithMetaFields怎麽用?PHP DAO::findByQueryWithMetaFields使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在DAO的用法示例。


在下文中一共展示了DAO::findByQueryWithMetaFields方法的2個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: findAll

 public function findAll($qbuilder)
 {
     if (UserSession::getInstance()->getAccessLevel() < 3) {
         die("<h1>Forbidden resource for you.</h1>");
     }
     @($dao = new DAO(Test));
     if (!isset($qbuilder)) {
         $qbuilder = new QueryBuilder('test');
         $qbuilder->addOrder("dsc_code", QueryBuilder::$ASC, 'discipline');
         $qbuilder->addOrder("tst_title", QueryBuilder::$ASC);
     }
     $qbuilder->addJoin("discipline", "tst_dsc_id", "dsc_id");
     $qbuilder->addLeftJoin("testproblems", "tst_id", "tpb_tst_id");
     $qbuilder->addGroupBy("tst_id", "test");
     $tests = $dao->findByQueryWithMetaFields($qbuilder);
     return $tests;
 }
開發者ID:renatorroliveira,項目名稱:algod,代碼行數:17,代碼來源:TestBS.php

示例2: findAll

 public function findAll($qbuilder)
 {
     if (UserSession::getInstance()->getAccessLevel() < 3) {
         die("<h1>Forbidden resource for you.</h1>");
     }
     @($dao = new DAO(Problem));
     if (!isset($qbuilder)) {
         $qbuilder = new QueryBuilder('problem');
         $qbuilder->addOrder("dsc_code", QueryBuilder::$ASC, 'discipline');
         $qbuilder->addOrder("prb_difficultyLevel", QueryBuilder::$ASC);
         $qbuilder->addOrder("prb_title", QueryBuilder::$ASC);
     }
     $qbuilder->addJoin("discipline", "prb_dsc_id", "dsc_id");
     $qbuilder->addLeftJoin("evaluationcase", "prb_id", "evc_prb_id");
     $qbuilder->addGroupBy("prb_id", "problem");
     $problems = $dao->findByQueryWithMetaFields($qbuilder);
     return $problems;
 }
開發者ID:renatorroliveira,項目名稱:algod,代碼行數:18,代碼來源:ProblemBS.php


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