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PHP Credentials::getUserName方法代碼示例

本文整理匯總了PHP中Credentials::getUserName方法的典型用法代碼示例。如果您正苦於以下問題:PHP Credentials::getUserName方法的具體用法?PHP Credentials::getUserName怎麽用?PHP Credentials::getUserName使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Credentials的用法示例。


在下文中一共展示了Credentials::getUserName方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: tryLogin

 public function tryLogin(Credentials $userCredentials, UserArray $users)
 {
     //First check to make sure the user is not already logged in (this is also checked in controller, but I prefer to check in all places to minimize errors)
     if (!$this->isUserLoggedIn()) {
         //If input matches any saved user, return true (successful login attempt) and save in session variable as 'logged in'
         if ($users->getUserByName($userCredentials->getUserName()) != null && password_verify($userCredentials->getUserPassword(), $users->getUserByName($userCredentials->getUserName())->getPassword())) {
             $_SESSION['LoggedIn'] = $userCredentials->getUserName();
             return true;
         }
     }
     //In all other cases, return false
     return false;
 }
開發者ID:jc222fi,項目名稱:PHP-assignment-2,代碼行數:13,代碼來源:LoginModel.php


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