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PHP ConsoleOption::get_info_filtered方法代碼示例

本文整理匯總了PHP中ConsoleOption::get_info_filtered方法的典型用法代碼示例。如果您正苦於以下問題:PHP ConsoleOption::get_info_filtered方法的具體用法?PHP ConsoleOption::get_info_filtered怎麽用?PHP ConsoleOption::get_info_filtered使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在ConsoleOption的用法示例。


在下文中一共展示了ConsoleOption::get_info_filtered方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: ConsoleOption

 * Author: Bluethrust Web Development
 * E-mail: support@bluethrust.com
 * Website: http://www.bluethrust.com
 *
 * License: http://www.bluethrust.com/license.php
 *
 */
include_once "../../../_setup.php";
include_once "../../../classes/member.php";
include_once "../../../classes/rank.php";
include_once "../../../classes/squad.php";
// Start Page
$consoleObj = new ConsoleOption($mysqli);
$cID = $consoleObj->findConsoleIDByName("View Your Squads");
$consoleObj->select($cID);
$consoleInfo = $consoleObj->get_info_filtered();
$member = new Member($mysqli);
$member->select($_SESSION['btUsername']);
$arrSquadPrivileges = $squadObj->arrSquadPrivileges;
$squadObj = new Squad($mysqli);
$squadAppObj = new Basic($mysqli, "squadapps", "squadapp_id");
// Check Login
$LOGIN_FAIL = true;
if ($member->authorizeLogin($_SESSION['btPassword']) && $member->hasAccess($consoleObj)) {
    $LOGIN_FAIL = false;
    $memberInfo = $member->get_info_filtered();
    if ($squadObj->select($_POST['sID']) && $squadObj->memberHasAccess($memberInfo['member_id'], "acceptapps") && $squadAppObj->select($_POST['saID'])) {
        $squadInfo = $squadObj->get_info_filtered();
        $squadAppInfo = $squadAppObj->get_info();
        $squadRankList = $squadObj->getRankList();
        if ($squadAppInfo['squad_id'] == $_POST['sID'] && $squadAppInfo['status'] == 0 && count($squadRankList) > 1) {
開發者ID:nsystem1,項目名稱:clanscripts,代碼行數:31,代碼來源:appdecision.php


注:本文中的ConsoleOption::get_info_filtered方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。