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PHP Bar::includes方法代碼示例

本文整理匯總了PHP中Bar::includes方法的典型用法代碼示例。如果您正苦於以下問題:PHP Bar::includes方法的具體用法?PHP Bar::includes怎麽用?PHP Bar::includes使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Bar的用法示例。


在下文中一共展示了Bar::includes方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: it_support_multiple_flat_joins

 /** @test */
 public function it_support_multiple_flat_joins()
 {
     $bar = Bar::includes('foo', 'baz')->where('foo.id', '=', 1)->where('baz.id', '=', 2)->first();
     $this->assertEquals('First Foo Second Baz Bar', $bar->title);
     $this->assertEquals('First Foo', $bar->foo->title);
     $this->assertEquals('Second Baz', $bar->baz->title);
     $this->assertQuery('select "foo"."id" as "__f__foo---id", "foo"."title" as "__f__foo---title", "foo"."created_at" as "__f__foo---created_at", "foo"."updated_at" as "__f__foo---updated_at", "baz"."id" as "__f__baz---id", "baz"."title" as "__f__baz---title", "baz"."created_at" as "__f__baz---created_at", "baz"."updated_at" as "__f__baz---updated_at", "bars".* from "bars" left join "foos" as "foo" on "foo"."id" = "bars"."foo_id" left join "bazs" as "baz" on "baz"."id" = "bars"."baz_id" where "foo"."id" = ? and "baz"."id" = ? limit 1');
     $this->assertQueryCount(1);
 }
開發者ID:leloulight,項目名稱:trigglog,代碼行數:10,代碼來源:WithJoinEloquentBuilderTest.php


注:本文中的Bar::includes方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。