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PHP Authority::getCurrentUser方法代碼示例

本文整理匯總了PHP中Authority::getCurrentUser方法的典型用法代碼示例。如果您正苦於以下問題:PHP Authority::getCurrentUser方法的具體用法?PHP Authority::getCurrentUser怎麽用?PHP Authority::getCurrentUser使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Authority的用法示例。


在下文中一共展示了Authority::getCurrentUser方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: function

*/
Route::filter('checkResourcePermission', function ($route, $request) {
    // Get request details
    $routeName = explode('.', Route::currentRouteName());
    $resource = $routeName[0];
    $action = $routeName[1];
    $item = $route->parameter($resource);
    // Replace laravel-style route action names with their CRUD equivalents
    $actionsToReplace = array('store', 'show', 'index', 'edit', 'destroy');
    $replaceWithAction = array('create', 'read', 'read', 'update', 'delete');
    $action = str_replace($actionsToReplace, $replaceWithAction, $action);
    // Check if user is forbidden from performing $action on $resource $item
    if (Authority::cannot($action, $resource, $item)) {
        return App::abort(403, 'You do not have permission to ' . $action . ' ' . $resource . ' ' . $item);
    }
});
/*
|--------------------------------------------------------------------------
| Role
|--------------------------------------------------------------------------
|
| Checks if the logged in user has been assigned the specified role
|
*/
Route::filter('hasRole', function ($route, $request, $value) {
    $user = Authority::getCurrentUser();
    // If not logged in or user does not have role
    if (!Auth::check() or !$user->hasRole($value)) {
        return App::abort(403, 'You must be assigned the role "' . $value . '" for this request');
    }
});
開發者ID:zeropingheroes,項目名稱:lanager-core,代碼行數:31,代碼來源:filters.php


注:本文中的Authority::getCurrentUser方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。