本文整理匯總了PHP中Artist::structureData方法的典型用法代碼示例。如果您正苦於以下問題：PHP Artist::structureData方法的具體用法？PHP Artist::structureData怎麽用？PHP Artist::structureData使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類Artist的用法示例。
在下文中一共展示了Artist::structureData方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的PHP代碼示例。
示例1: testStructureData
/**
* @covers Artist::structureData
*/
public function testStructureData()
{
$this->object->id = '50';
$this->object->name = 'artistName50';
$artist = $this->object->structureData();
$this->assertInstanceOf(Artist::class, $artist, 'Result should be an instance of Artist class');
$this->assertEquals(50, $artist->id, 'Id should be convert in integer');
$this->assertEquals('artistName50', $artist->name, 'Name should be set to artistName50, but found:' . $artist->name);
}示例2: Artist
$api->output(403, 'Admin scope is required for editing artist');
//indicate the requester do not have the required scope for updating artist
return;
}
if (!$api->checkParameterExists('id', $id)) {
$api->output(400, 'Artist identifier must be provided');
//artist was not provided, return an error
return;
}
$artist = new Artist($id);
if (!$artist->populate(['id' => $id])) {
$api->output(404, 'Artist not found');
//indicate the artist was not found
return;
}
//adapt and validate object received
$updatedArtist = $api->query['body'];
if (!$artist->validateModel($updatedArtist, $errorMessage)) {
$api->output(400, 'Artist is not valid: ' . $errorMessage);
//provided user is not valid
return;
}
if (!$artist->update($errorMessage)) {
$api->output(500, 'Error during artist update' . $errorMessage);
//something gone wrong :(
return;
}
$artist->getTracks();
$api->output(200, $artist->structureData());
break;
}