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PHP Application_Model_User::isSuperAdmin方法代碼示例

本文整理匯總了PHP中Application_Model_User::isSuperAdmin方法的典型用法代碼示例。如果您正苦於以下問題:PHP Application_Model_User::isSuperAdmin方法的具體用法?PHP Application_Model_User::isSuperAdmin怎麽用?PHP Application_Model_User::isSuperAdmin使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在Application_Model_User的用法示例。


在下文中一共展示了Application_Model_User::isSuperAdmin方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的PHP代碼示例。

示例1: userCan

 /**
  * Still playing around with how I want to handle permissions.
  * This is a method that can be called before each action to 
  * see if the user can do what they are asking to.
  * 
  * @access public
  * @return void
  */
 protected function userCan()
 {
     // User can edit themselves
     if ($this->id == $this->user->getId()) {
         return true;
     }
     // TODO: Need to expand upon this? Probably...
     // we can add in what the user is trying to do, and check perms
     // on top of just ownership. This will do for now.
     if ($this->id) {
         if ($this->user->isParentOf($this->id) || $this->user->isSuperAdmin()) {
             return true;
         }
     } else {
         // If there was no id already set, we are probably adding a folder.
         // TODO: Need to handle perms somehow here.
         return true;
     }
     // Set this entity to not valid so we do not give anything away
     // TODO: Maybe make a default() method that we can reset a built entity to it's defaults.
     // defaults could be set from the entity profile.
     $this->valid = false;
     $this->error = 'User does not have permission to execute the request.';
     //$this->error = 'ID does not exist for this user.';
     return false;
 }
開發者ID:fniftaly,項目名稱:Java-Selenium,代碼行數:34,代碼來源:Entityabstract.php


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