本文整理匯總了Java中org.hibernate.usertype.UserType.sqlTypes方法的典型用法代碼示例。如果您正苦於以下問題：Java UserType.sqlTypes方法的具體用法？Java UserType.sqlTypes怎麽用？Java UserType.sqlTypes使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類org.hibernate.usertype.UserType的用法示例。
在下文中一共展示了UserType.sqlTypes方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: CustomType
import org.hibernate.usertype.UserType; //導入方法依賴的package包/類
public CustomType(UserType userType, String[] registrationKeys) throws MappingException {
this.userType = userType;
this.name = userType.getClass().getName();
this.types = userType.sqlTypes();
this.dictatedSizes = Sized.class.isInstance( userType )
? ( (Sized) userType ).dictatedSizes()
: new Size[ types.length ];
this.defaultSizes = Sized.class.isInstance( userType )
? ( (Sized) userType ).defaultSizes()
: new Size[ types.length ];
this.customLogging = LoggableUserType.class.isInstance( userType );
this.registrationKeys = registrationKeys;
}
示例2: CustomType
import org.hibernate.usertype.UserType; //導入方法依賴的package包/類
public CustomType(Class userTypeClass, Properties parameters) throws MappingException {
if ( !UserType.class.isAssignableFrom( userTypeClass ) ) {
throw new MappingException(
"Custom type does not implement UserType: " +
userTypeClass.getName()
);
}
name = userTypeClass.getName();
try {
userType = ( UserType ) userTypeClass.newInstance();
}
catch ( InstantiationException ie ) {
throw new MappingException(
"Cannot instantiate custom type: " +
userTypeClass.getName()
);
}
catch ( IllegalAccessException iae ) {
throw new MappingException(
"IllegalAccessException trying to instantiate custom type: " +
userTypeClass.getName()
);
}
TypeFactory.injectParameters( userType, parameters );
types = userType.sqlTypes();
customLogging = LoggableUserType.class.isAssignableFrom( userTypeClass );
}