本文整理匯總了Java中org.apache.http.params.HttpProtocolParams.getUserAgent方法的典型用法代碼示例。如果您正苦於以下問題：Java HttpProtocolParams.getUserAgent方法的具體用法？Java HttpProtocolParams.getUserAgent怎麽用？Java HttpProtocolParams.getUserAgent使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類org.apache.http.params.HttpProtocolParams的用法示例。
在下文中一共展示了HttpProtocolParams.getUserAgent方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: process
import org.apache.http.params.HttpProtocolParams; //導入方法依賴的package包/類
public void process(final HttpRequest request, final HttpContext context)
throws HttpException, IOException {
if (request == null) {
throw new IllegalArgumentException("HTTP request may not be null");
}
if (!request.containsHeader(HTTP.USER_AGENT)) {
String useragent = HttpProtocolParams.getUserAgent(request.getParams());
if (useragent != null) {
request.addHeader(HTTP.USER_AGENT, useragent);
}
}
}
示例2: getUserAgent
import org.apache.http.params.HttpProtocolParams; //導入方法依賴的package包/類
/**
*
* @return the User-Agent that HttpClient is currently using.
*/
public String getUserAgent() {
return HttpProtocolParams.getUserAgent(this.client.getParams());
}