本文整理匯總了Java中javax.swing.JMenu.getLocationOnScreen方法的典型用法代碼示例。如果您正苦於以下問題：Java JMenu.getLocationOnScreen方法的具體用法？Java JMenu.getLocationOnScreen怎麽用？Java JMenu.getLocationOnScreen使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類javax.swing.JMenu的用法示例。
在下文中一共展示了JMenu.getLocationOnScreen方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: runActualTest
import javax.swing.JMenu; //導入方法依賴的package包/類
private static void runActualTest(GraphicsDevice device,
CountDownLatch latch,
JFrame frame,
boolean [] result)
{
Rectangle screenBounds = setLocation(frame, device);
JMenu menu = frame.getJMenuBar().getMenu(0);
menu.doClick();
Point location = menu.getLocationOnScreen();
JPopupMenu pm = menu.getPopupMenu();
Dimension pmSize = pm.getSize();
int yOffset = UIManager.getInt("Menu.submenuPopupOffsetY");
int height = location.y + yOffset + pmSize.height + menu.getHeight();
int available = screenBounds.y + screenBounds.height - height;
if (available > 0) {
Point origin = pm.getLocationOnScreen();
if (origin.y < location.y) {
// growing upward, wrong!
result[0] = false;
} else {
// growing downward, ok!
result[0] = true;
}
} else {
// there is no space, growing upward would be ok, so we pass
result[0] = true;
}
}