本文整理匯總了Java中javax.sound.sampled.AudioInputStream.reset方法的典型用法代碼示例。如果您正苦於以下問題：Java AudioInputStream.reset方法的具體用法？Java AudioInputStream.reset怎麽用？Java AudioInputStream.reset使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類javax.sound.sampled.AudioInputStream的用法示例。
在下文中一共展示了AudioInputStream.reset方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: main
import javax.sound.sampled.AudioInputStream; //導入方法依賴的package包/類
public static void main(String[] args) throws Exception {
AudioFloatFormatConverter converter = new AudioFloatFormatConverter();
byte[] data = { 10, 20, 30, 40, 30, 20, 10 };
AudioFormat format = new AudioFormat(8000, 8, 1, true, false);
AudioFormat format2 = new AudioFormat(16000, 8, 1, true, false);
AudioInputStream ais = new AudioInputStream(new ByteArrayInputStream(
data), format, data.length);
AudioInputStream ais2 = converter.getAudioInputStream(format2, ais);
byte[] data2 = new byte[30];
int ret = ais2.read(data2, 0, data2.length);
ais.reset();
AudioInputStream ais3 = converter.getAudioInputStream(format2, ais);
byte[] data3 = new byte[100];
ais3.skip(7);
int ret2 = ais3.read(data3, 7, data3.length);
if (ret2 != ret - 7)
throw new Exception("Skip doesn't work correctly (" + ret2 + " != "
+ (ret - 7) + ")");
for (int i = 7; i < ret2 + 7; i++) {
if (data3[i] != data2[i])
throw new Exception("Skip doesn't work correctly (" + data3[i]
+ " != " + data2[i] + ")");
}
}