本文整理匯總了Java中javax.persistence.metamodel.SingularAttribute.isAssociation方法的典型用法代碼示例。如果您正苦於以下問題：Java SingularAttribute.isAssociation方法的具體用法？Java SingularAttribute.isAssociation怎麽用？Java SingularAttribute.isAssociation使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類javax.persistence.metamodel.SingularAttribute的用法示例。
在下文中一共展示了SingularAttribute.isAssociation方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: containsRelation
import javax.persistence.metamodel.SingularAttribute; //導入方法依賴的package包/類
public static boolean containsRelation(Object expr) {
if (expr instanceof Join) {
return true;
} else if (expr instanceof SingularAttribute) {
SingularAttribute<?, ?> attr = (SingularAttribute<?, ?>) expr;
return attr.isAssociation();
} else if (expr instanceof Path) {
Path<?> attrPath = (Path<?>) expr;
Bindable<?> model = attrPath.getModel();
Path<?> parent = attrPath.getParentPath();
return containsRelation(parent) || containsRelation(model);
} else {
// we may can do better here...
return false;
}
}
示例2: containsRelation
import javax.persistence.metamodel.SingularAttribute; //導入方法依賴的package包/類
public static boolean containsRelation(Object expr) {
if (expr instanceof Join) {
return true;
}
else if (expr instanceof SingularAttribute) {
SingularAttribute<?, ?> attr = (SingularAttribute<?, ?>) expr;
return attr.isAssociation();
}
else if (expr instanceof Path) {
Path<?> attrPath = (Path<?>) expr;
Bindable<?> model = attrPath.getModel();
Path<?> parent = attrPath.getParentPath();
return containsRelation(parent) || containsRelation(model);
}
else {
// we may can do better here...
return false;
}
}