本文整理匯總了Java中java.util.concurrent.Semaphore.availablePermits方法的典型用法代碼示例。如果您正苦於以下問題：Java Semaphore.availablePermits方法的具體用法？Java Semaphore.availablePermits怎麽用？Java Semaphore.availablePermits使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類java.util.concurrent.Semaphore的用法示例。
在下文中一共展示了Semaphore.availablePermits方法的2個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: removeAddress
import java.util.concurrent.Semaphore; //導入方法依賴的package包/類
public boolean removeAddress(String address) {
Semaphore semaphore = this.addressSemaphoreMap.get(address);
if (semaphore.availablePermits() == this.poolNum) {
this.addressSemaphoreMap.remove(address);
return true;
}
return false;
}
示例2: testReleaseAcquireDifferentThreads
import java.util.concurrent.Semaphore; //導入方法依賴的package包/類
public void testReleaseAcquireDifferentThreads(boolean fair,
final AcquireMethod acquirer) {
final Semaphore s = new Semaphore(0, fair);
final int rounds = 4;
long startTime = System.nanoTime();
Thread t = newStartedThread(new CheckedRunnable() {
public void realRun() throws InterruptedException {
for (int i = 0; i < rounds; i++) {
assertFalse(s.hasQueuedThreads());
if (i % 2 == 0)
acquirer.acquire(s);
else
acquirer.acquire(s, 3);
}}});
for (int i = 0; i < rounds; i++) {
while (! (s.availablePermits() == 0 && s.hasQueuedThreads()))
Thread.yield();
assertTrue(t.isAlive());
if (i % 2 == 0)
s.release();
else
s.release(3);
}
awaitTermination(t);
assertEquals(0, s.availablePermits());
assertTrue(millisElapsedSince(startTime) < LONG_DELAY_MS);
}