本文整理匯總了Java中java.util.concurrent.ConcurrentSkipListMap.keySet方法的典型用法代碼示例。如果您正苦於以下問題：Java ConcurrentSkipListMap.keySet方法的具體用法？Java ConcurrentSkipListMap.keySet怎麽用？Java ConcurrentSkipListMap.keySet使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類java.util.concurrent.ConcurrentSkipListMap的用法示例。
在下文中一共展示了ConcurrentSkipListMap.keySet方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: testKeySetOrder
import java.util.concurrent.ConcurrentSkipListMap; //導入方法依賴的package包/類
/**
* keySet is ordered
*/
public void testKeySetOrder() {
ConcurrentSkipListMap map = map5();
Set s = map.keySet();
Iterator i = s.iterator();
Integer last = (Integer)i.next();
assertEquals(last, one);
int count = 1;
while (i.hasNext()) {
Integer k = (Integer)i.next();
assertTrue(last.compareTo(k) < 0);
last = k;
++count;
}
assertEquals(5, count);
}
示例2: testKeySetToArray
import java.util.concurrent.ConcurrentSkipListMap; //導入方法依賴的package包/類
/**
* keySet.toArray returns contains all keys
*/
public void testKeySetToArray() {
ConcurrentSkipListMap map = map5();
Set s = map.keySet();
Object[] ar = s.toArray();
assertTrue(s.containsAll(Arrays.asList(ar)));
assertEquals(5, ar.length);
ar[0] = m10;
assertFalse(s.containsAll(Arrays.asList(ar)));
}
示例3: testKeySet
import java.util.concurrent.ConcurrentSkipListMap; //導入方法依賴的package包/類
/**
* keySet returns a Set containing all the keys
*/
public void testKeySet() {
ConcurrentSkipListMap map = map5();
Set s = map.keySet();
assertEquals(5, s.size());
assertTrue(s.contains(one));
assertTrue(s.contains(two));
assertTrue(s.contains(three));
assertTrue(s.contains(four));
assertTrue(s.contains(five));
}