本文整理匯總了Java中java.time.LocalTime.minusNanos方法的典型用法代碼示例。如果您正苦於以下問題：Java LocalTime.minusNanos方法的具體用法？Java LocalTime.minusNanos怎麽用？Java LocalTime.minusNanos使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類java.time.LocalTime的用法示例。
在下文中一共展示了LocalTime.minusNanos方法的4個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: test_minusNanos_halfABillion
import java.time.LocalTime; //導入方法依賴的package包/類
@Test
public void test_minusNanos_halfABillion() {
LocalTime t = LocalTime.MIDNIGHT;
int hour = 0;
int min = 0;
int sec = 0;
int nanos = 0;
for (long i = 0; i < 3700 * 1000000000L; i+= 500000000) {
t = t.minusNanos(500000000);
nanos -= 500000000;
if (nanos < 0) {
sec--;
nanos += 1000000000;
if (sec == -1) {
min--;
sec += 60;
if (min == -1) {
hour--;
min += 60;
if (hour == -1) {
hour += 24;
}
}
}
}
assertEquals(t.getHour(), hour);
assertEquals(t.getMinute(), min);
assertEquals(t.getSecond(), sec);
assertEquals(t.getNano(), nanos);
}
}
示例2: test_minusNanos_fromZero
import java.time.LocalTime; //導入方法依賴的package包/類
@Test(dataProvider="minusNanos_fromZero")
public void test_minusNanos_fromZero(long nanoseconds, int hour, int min, int sec, int nanos) {
LocalTime base = LocalTime.MIDNIGHT;
LocalTime t = base.minusNanos(nanoseconds);
assertEquals(hour, t.getHour());
assertEquals(min, t.getMinute());
assertEquals(sec, t.getSecond());
assertEquals(nanos, t.getNano());
}
示例3: test_toNanoOfDay
import java.time.LocalTime; //導入方法依賴的package包/類
@Test
public void test_toNanoOfDay() {
LocalTime t = LocalTime.of(0, 0);
for (int i = 0; i < 1000000; i++) {
assertEquals(t.toNanoOfDay(), i);
t = t.plusNanos(1);
}
t = LocalTime.of(0, 0);
for (int i = 1; i <= 1000000; i++) {
t = t.minusNanos(1);
assertEquals(t.toNanoOfDay(), 24 * 60 * 60 * 1000000000L - i);
}
}
示例4: test_toNanoOfDay_fromNanoOfDay_symmetry
import java.time.LocalTime; //導入方法依賴的package包/類
@Test
public void test_toNanoOfDay_fromNanoOfDay_symmetry() {
LocalTime t = LocalTime.of(0, 0);
for (int i = 0; i < 1000000; i++) {
assertEquals(LocalTime.ofNanoOfDay(t.toNanoOfDay()), t);
t = t.plusNanos(1);
}
t = LocalTime.of(0, 0);
for (int i = 1; i <= 1000000; i++) {
t = t.minusNanos(1);
assertEquals(LocalTime.ofNanoOfDay(t.toNanoOfDay()), t);
}
}