本文整理匯總了Java中ij.process.ImageProcessor.copyBits方法的典型用法代碼示例。如果您正苦於以下問題：Java ImageProcessor.copyBits方法的具體用法？Java ImageProcessor.copyBits怎麽用？Java ImageProcessor.copyBits使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類ij.process.ImageProcessor的用法示例。
在下文中一共展示了ImageProcessor.copyBits方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: dilate
import ij.process.ImageProcessor; //導入方法依賴的package包/類
private void dilate(ByteProcessor ip, int[][] H) {
if (H == null) {
IJ.error("no structuring element");
return;
}
//assume that the hot spot of se is at its center (ic,jc)
int ic = (H[0].length - 1) / 2;
int jc = (H.length - 1) / 2;
int N = H.length * H[0].length;
ImageProcessor tmp = ip.createProcessor(ip.getWidth(), ip.getHeight());
int k = 0;
IJ.showProgress(k, N);
for (int j = 0; j < H.length; j++) {
for (int i = 0; i < H[j].length; i++) {
if (H[j][i] > 0) { // this element is set
// copy image into position (u-ch,v-cv)
tmp.copyBits(ip, i - ic, j - jc, Blitter.MAX);
}
IJ.showProgress(k++, N);
}
}
ip.copyBits(tmp, 0, 0, Blitter.COPY);
}
示例2: dilate
import ij.process.ImageProcessor; //導入方法依賴的package包/類
void dilate(ImageProcessor ip, int[][] H){
if (H == null) {
IJ.error("no structuring element");
return;
}
//assume that the hot spot of se is at its center (ic,jc)
int ic = (H[0].length - 1) / 2;
int jc = (H.length - 1) / 2;
int N = H.length * H[0].length;
ImageProcessor tmp = ip.createProcessor(ip.getWidth(),ip.getHeight());
int k = 0;
IJ.showProgress(k,N);
for (int j = 0; j < H.length; j++) {
for (int i = 0; i < H[j].length; i++) {
if (H[j][i] > 0) { // this pixel is set
// copy image into position (u-ch,v-cv)
tmp.copyBits(ip, i - ic, j - jc, Blitter.MAX);
}
IJ.showProgress(k++, N);
}
}
ip.copyBits(tmp, 0, 0, Blitter.COPY);
}
示例3: outline
import ij.process.ImageProcessor; //導入方法依賴的package包/類
void outline(ImageProcessor ip){
int[][] H = {{0,1,0},
{1,1,1},
{0,1,0}
};
ImageProcessor foreground = ip.duplicate();
erode(foreground,H);
ip.copyBits(foreground,0,0,Blitter.DIFFERENCE);
}