本文整理匯總了Java中android.widget.AbsListView.smoothScrollToPosition方法的典型用法代碼示例。如果您正苦於以下問題：Java AbsListView.smoothScrollToPosition方法的具體用法？Java AbsListView.smoothScrollToPosition怎麽用？Java AbsListView.smoothScrollToPosition使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類android.widget.AbsListView的用法示例。
在下文中一共展示了AbsListView.smoothScrollToPosition方法的1個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的Java代碼示例。
示例1: scrollChildToNextItem
import android.widget.AbsListView; //導入方法依賴的package包/類
/**
* 將子視圖滑動到下一個單元的位置
*/
private void scrollChildToNextItem() {
if (!canChildScrollDown()) {
return;
}
if (mTarget instanceof AbsListView) {
AbsListView absListView = (AbsListView) mTarget;
int currentPosition = absListView.getLastVisiblePosition();
if (absListViewScrollListener != null) {
absListViewScrollListener.setSwallowNextScroll(true);
}
absListView.smoothScrollToPosition(currentPosition + 1);
} else if (mTarget instanceof RecyclerView) {
RecyclerView.LayoutManager layoutManager = ((RecyclerView) mTarget).getLayoutManager();
int lastPosition = 1;
if (layoutManager instanceof LinearLayoutManager) {
lastPosition = ((LinearLayoutManager) layoutManager).findLastVisibleItemPosition();
} else if (layoutManager instanceof StaggeredGridLayoutManager) {
int[] positions = ((StaggeredGridLayoutManager) layoutManager).findLastVisibleItemPositions(null);
for (int position : positions) {
if (position > lastPosition) {
lastPosition = position;
}
}
}
if (recyclerScrollListener != null) {
recyclerScrollListener.setSwallowNextScroll(true);
}
layoutManager.scrollToPosition(lastPosition + 1);
}
}