Golang QuadStore.ValueOf方法代碼示例

func hasaWithTag(qs graph.QuadStore, tag string, target string) *HasA {
	and := NewAnd(qs)

	obj := qs.FixedIterator()
	obj.Add(qs.ValueOf(quad.Raw(target)))
	obj.Tagger().Add(tag)
	and.AddSubIterator(NewLinksTo(qs, obj, quad.Object))

	pred := qs.FixedIterator()
	pred.Add(qs.ValueOf(quad.Raw("status")))
	and.AddSubIterator(NewLinksTo(qs, pred, quad.Predicate))

	return NewHasA(qs, and, quad.Subject)
}

func buildHas(qs graph.QuadStore, via interface{}, in graph.Iterator, reverse bool, nodes []string) graph.Iterator {
	viaIter := buildViaPath(qs, via).
		BuildIterator()
	ends := func() graph.Iterator {
		if len(nodes) == 0 {
			return qs.NodesAllIterator()
		}

		fixed := qs.FixedIterator()
		for _, n := range nodes {
			fixed.Add(qs.ValueOf(n))
		}
		return fixed
	}()

	start, goal := quad.Subject, quad.Object
	if reverse {
		start, goal = goal, start
	}

	trail := iterator.NewLinksTo(qs, viaIter, quad.Predicate)
	dest := iterator.NewLinksTo(qs, ends, goal)

	// If we were given nodes, intersecting with them first will
	// be extremely cheap-- otherwise, it will be the most expensive
	// (requiring iteration over all nodes). We have enough info to
	// make this optimization now since intersections are commutative
	if len(nodes) == 0 { // Where dest involves an All iterator.
		route := join(qs, trail, dest)
		has := iterator.NewHasA(qs, route, start)
		return join(qs, in, has)
	}

	// This looks backwards. That's OK-- see the note above.
	route := join(qs, dest, trail)
	has := iterator.NewHasA(qs, route, start)
	return join(qs, has, in)
}

func buildIteratorTree(tree *peg.ExpressionTree, qs graph.QuadStore) graph.Iterator {
	switch tree.Name {
	case "Start":
		return buildIteratorTree(tree.Children[0], qs)
	case "NodeIdentifier":
		var out graph.Iterator
		nodeID := getIdentString(tree)
		if tree.Children[0].Name == "Variable" {
			allIt := qs.NodesAllIterator()
			allIt.Tagger().Add(nodeID)
			out = allIt
		} else {
			n := nodeID
			if tree.Children[0].Children[0].Name == "ColonIdentifier" {
				n = nodeID[1:]
			}
			fixed := qs.FixedIterator()
			fixed.Add(qs.ValueOf(n))
			out = fixed
		}
		return out
	case "PredIdentifier":
		i := 0
		if tree.Children[0].Name == "Reverse" {
			//Taken care of below
			i++
		}
		it := buildIteratorTree(tree.Children[i], qs)
		lto := iterator.NewLinksTo(qs, it, quad.Predicate)
		return lto
	case "RootConstraint":
		constraintCount := 0
		and := iterator.NewAnd(qs)
		for _, c := range tree.Children {
			switch c.Name {
			case "NodeIdentifier":
				fallthrough
			case "Constraint":
				it := buildIteratorTree(c, qs)
				and.AddSubIterator(it)
				constraintCount++
				continue
			default:
				continue
			}
		}
		return and
	case "Constraint":
		var hasa *iterator.HasA
		topLevelDir := quad.Subject
		subItDir := quad.Object
		subAnd := iterator.NewAnd(qs)
		isOptional := false
		for _, c := range tree.Children {
			switch c.Name {
			case "PredIdentifier":
				if c.Children[0].Name == "Reverse" {
					topLevelDir = quad.Object
					subItDir = quad.Subject
				}
				it := buildIteratorTree(c, qs)
				subAnd.AddSubIterator(it)
				continue
			case "PredicateKeyword":
				switch c.Children[0].Name {
				case "OptionalKeyword":
					isOptional = true
				}
			case "NodeIdentifier":
				fallthrough
			case "RootConstraint":
				it := buildIteratorTree(c, qs)
				l := iterator.NewLinksTo(qs, it, subItDir)
				subAnd.AddSubIterator(l)
				continue
			default:
				continue
			}
		}
		hasa = iterator.NewHasA(qs, subAnd, topLevelDir)
		if isOptional {
			optional := iterator.NewOptional(hasa)
			return optional
		}
		return hasa
	default:
		return &iterator.Null{}
	}
}