本文整理匯總了C#中NHibernate.Mapping.ByCode.ExplicitlyDeclaredModel.IsPersistentId方法的典型用法代碼示例。如果您正苦於以下問題：C# ExplicitlyDeclaredModel.IsPersistentId方法的具體用法？C# ExplicitlyDeclaredModel.IsPersistentId怎麽用？C# ExplicitlyDeclaredModel.IsPersistentId使用的例子？那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在類NHibernate.Mapping.ByCode.ExplicitlyDeclaredModel的用法示例。
在下文中一共展示了ExplicitlyDeclaredModel.IsPersistentId方法的3個代碼示例，這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚，您的評價將有助於係統推薦出更棒的C#代碼示例。
示例1: WhenPropertyUsedAsPoidThenRegister
public void WhenPropertyUsedAsPoidThenRegister()
{
var inspector = new ExplicitlyDeclaredModel();
var mapper = new ModelMapper(inspector);
mapper.Class<MyClass>(map => map.Id(x => x.Id, idmap => { }));
Assert.That(inspector.IsPersistentId(For<MyClass>.Property(x => x.Id)), Is.True);
}示例2: WhenPropertyUsedAsComposedIdThenRegister
public void WhenPropertyUsedAsComposedIdThenRegister()
{
var inspector = new ExplicitlyDeclaredModel();
var mapper = new ModelMapper(inspector);
mapper.Class<MyClass>(map => map.ComponentAsId(x => x.Id));
inspector.IsPersistentId(For<MyClass>.Property(x => x.Id)).Should().Be.True();
inspector.IsPersistentProperty(For<MyClass>.Property(x => x.Id)).Should().Be.True();
inspector.IsComponent(typeof(IMyCompo)).Should().Be.True();
}示例3: WhenPropertyUsedAsComposedIdThenRegister
public void WhenPropertyUsedAsComposedIdThenRegister()
{
var inspector = new ExplicitlyDeclaredModel();
var mapper = new ModelMapper(inspector);
mapper.Class<MyClass>(map =>
map.ComposedId(cm=>
{
cm.Property(x => x.Code);
cm.ManyToOne(x => x.Relation);
})
);
inspector.IsMemberOfComposedId(For<MyClass>.Property(x => x.Code)).Should().Be.True();
inspector.IsMemberOfComposedId(For<MyClass>.Property(x => x.Relation)).Should().Be.True();
inspector.IsPersistentProperty(For<MyClass>.Property(x => x.Code)).Should().Be.True();
inspector.IsPersistentProperty(For<MyClass>.Property(x => x.Relation)).Should().Be.True();
inspector.IsPersistentId(For<MyClass>.Property(x => x.Code)).Should().Be.False();
inspector.IsPersistentId(For<MyClass>.Property(x => x.Relation)).Should().Be.False();
}