當前位置: 首頁>>代碼示例>>C#>>正文


C# BoundingBox.smallestArea方法代碼示例

本文整理匯總了C#中BoundingBox.smallestArea方法的典型用法代碼示例。如果您正苦於以下問題:C# BoundingBox.smallestArea方法的具體用法?C# BoundingBox.smallestArea怎麽用?C# BoundingBox.smallestArea使用的例子?那麽, 這裏精選的方法代碼示例或許可以為您提供幫助。您也可以進一步了解該方法所在BoundingBox的用法示例。


在下文中一共展示了BoundingBox.smallestArea方法的1個代碼示例,這些例子默認根據受歡迎程度排序。您可以為喜歡或者感覺有用的代碼點讚,您的評價將有助於係統推薦出更棒的C#代碼示例。

示例1: KawigiEdit_RunTest

 private static Boolean KawigiEdit_RunTest(int testNum, int[] p0, int[] p1, Boolean hasAnswer, int p2)
 {
     Console.Write("Test " + testNum + ": [" + "{");
     for (int i = 0; p0.Length > i; ++i) {
         if (i > 0) {
             Console.Write(",");
         }
         Console.Write(p0[i]);
     }
     Console.Write("}" + "," + "{");
     for (int i = 0; p1.Length > i; ++i) {
         if (i > 0) {
             Console.Write(",");
         }
         Console.Write(p1[i]);
     }
     Console.Write("}");
     Console.WriteLine("]");
     BoundingBox obj;
     int answer;
     obj = new BoundingBox();
     DateTime startTime = DateTime.Now;
     answer = obj.smallestArea(p0, p1);
     DateTime endTime = DateTime.Now;
     Boolean res;
     res = true;
     Console.WriteLine("Time: " + (endTime - startTime).TotalSeconds + " seconds");
     if (hasAnswer) {
         Console.WriteLine("Desired answer:");
         Console.WriteLine("\t" + p2);
     }
     Console.WriteLine("Your answer:");
     Console.WriteLine("\t" + answer);
     if (hasAnswer) {
         res = answer == p2;
     }
     if (!res) {
         Console.WriteLine("DOESN'T MATCH!!!!");
     } else if ((endTime - startTime).TotalSeconds >= 2) {
         Console.WriteLine("FAIL the timeout");
         res = false;
     } else if (hasAnswer) {
         Console.WriteLine("Match :-)");
     } else {
         Console.WriteLine("OK, but is it right?");
     }
     Console.WriteLine("");
     return res;
 }
開發者ID:root85,項目名稱:olymp-programming,代碼行數:49,代碼來源:BoundingBox.cs


注:本文中的BoundingBox.smallestArea方法示例由純淨天空整理自Github/MSDocs等開源代碼及文檔管理平台,相關代碼片段篩選自各路編程大神貢獻的開源項目,源碼版權歸原作者所有,傳播和使用請參考對應項目的License;未經允許,請勿轉載。