Subset.bitlist_from_subset():bitlist_from_subset()是一個sympy Python庫函數,它返回與子集相對應的位列表。
用法:
sympy.combinatorics.subset.Subset.bitlist_from_subset()
返回:
對應於子集的位列表
代碼1:bitlist_from_subset()示例
# Python code explaining 
# SymPy.Subset.bitlist_from_subset() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.bitlist_from_subset() 
  
# Creating Subset 
a = Subset.bitlist_from_subset(['c', 'd'], ['geek', 'for', 'c', 'd']) 
  
# bitlist_from_subset value 
print ("Subset a bitlist_from_subset : ", a)輸出:
Subset a bitlist_from_subset : 0011
代碼2:bitlist_from_subset()示例
# Python code explaining 
# SymPy.Subset.bitlist_from_subset() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.bitlist_from_subset() 
  
# Creating Subset 
a = Subset.bitlist_from_subset(['1', '2'], ['4', '3', 'c', 'd']) 
  
# bitlist_from_subset value 
print ("Subset a bitlist_from_subset : ", a)輸出:
Subset a bitlist_from_subset : 0000
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