Python Sympy Polyhedron.cyclic_form()用法及代碼示例

Polyhedron.cyclic_form()：cyclic_form()是一個sympy Python庫函數，它以循環符號返回角的索引。

用法：

sympy.combinatorics.Polyhedrons.Polyhedron.cyclic_form()

返回：
循環符號中的角索引

代碼1：cyclic_form()示例–四麵體

# Python code explaining 
# SymPy.Polyhedron.cyclic_form() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.polyhedron import tetrahedron, octahedron 
  
# Using from  
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form() 
  
# Creating Polyhedron 
a = tetrahedron.copy() 
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form) 
  
a.rotate(0) 
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)

輸出：

Polyhedron – cyclic_form form : []

Polyhedron – cyclic_form form : [[1, 2, 3]]

代碼2：cyclic_form()示例–八麵體

# Python code explaining 
# SymPy.Polyhedron.cyclic_form() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.polyhedron import tetrahedron, octahedron 
  
# Using from  
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form() 
  
# Creating Polyhedron 
a = octahedron.copy() 
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form) 
  
a.rotate(0) 
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)

輸出：

Polyhedron – cyclic_form form : []

Polyhedron – cyclic_form form : [[1, 2, 3, 4]]

相關用法

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