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Python Sympy Partition.prev_lex()用法及代碼示例


Partition.prev_lex():prev_lex()是一個sympy Python庫函數,按字典順序返回前一個整數分區n。如果分區為[1,…,1],則此順序環繞[n]。

用法: sympy.combinatorics.partitions.Partition.prev_lex()

返回:前一個整數分區,按字母順序排列n


代碼1:prev_lex()示例

] 
  
# Python code explaining 
# SymPy.prev_lex() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.partitions import IntegerPartition 
  
# Using from sympy.combinatorics.partitions.Partition.prev_lex() method  
p = IntegerPartition([312, 121, 14, 5]) 
  
print('p : ', p) 
print('\nPrevious Integrer : ', p.prev_lex())

輸出:

p : [312, 121, 14, 5]

Previous Integrer : [312, 121, 14, 4, 1]

代碼2:prev_lex()示例

] 
  
# Python code explaining 
# SymPy.prev_lex() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.partitions import IntegerPartition 
  
# Using from sympy.combinatorics.partitions.Partition.prev_lex() method  
p = IntegerPartition([1, 312, 121, 14,  
                      34, 56, 32]) 
  
print('p : ', p) 
print('\nPrevious Integrer : ', p.prev_lex())

輸出:

p : [312, 121, 56, 34, 32, 14, 1]

Previous Integrer : [312, 121, 56, 34, 32, 13, 2]



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注:本文由純淨天空篩選整理自noobestars101大神的英文原創作品 SymPy | Partition.prev_lex() in Python。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。