實例方法
last(where:)
返回滿足給定謂詞的序列的最後一個元素。
聲明
func last(where predicate: (Self.Element) throws -> Bool) rethrows -> Self.Element?
返回值
滿足 predicate
的序列的最後一個元素,如果沒有滿足 predicate
的元素,則為 nil
。
參數
predicate
一個閉包,它將序列的一個元素作為其參數,並返回一個布爾值,指示該元素是否匹配。
詳述
此示例使用 last(where:)
方法查找整數數組中的最後一個負數:
let numbers = [3, 7, 4, -2, 9, -6, 10, 1]
if let lastNegative = numbers.last(where: { $0 < 0 }) {
print("The last negative number is \(lastNegative).")
}
// Prints "The last negative number is -6."
可用版本
iOS 8.0+, iPadOS 8.0+, macOS 10.10+, Mac Catalyst 13.0+, tvOS 9.0+, watchOS 2.0+
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注:本文由純淨天空篩選整理自apple.com大神的英文原創作品 String.UnicodeScalarView last(where:)。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。