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Java StrictMath exp()用法及代碼示例


java.lang.StrictMath類的所有方法:設置1,設置2 java.lang.StrictMath.exp()是Java中的一種內置方法,用於返回歐拉數,該歐拉數提高為指定的雙精度值的冪。它產生三個特殊結果:

  • 當給定參數為正無窮大時,結果為正無窮大。
  • 當參數為負無窮大時,結果為正零。
  • 當給定參數為NaN時,結果為NaN。

用法:

public static double exp(double num)

參數:此方法接受一個雙精度類型的參數num,它是將e提高到的 index 。


返回值:該方法返回值e^num,其中e是自然對數的底數。

例子:

Input:num = 7
Output:1096.6331584284585

Input:num = (1.0 / 0.0)
Output:Infinity

下麵的程序演示了java.lang.StrictMath.exp()方法:
程序1:

// Java praogram to illustrate the 
// java.lang.StrictMath.exp() 
import java.lang.*; 
  
public class Geeks { 
  
    public static void main(String[] args) 
    { 
  
        double num1 = 0.0, num2 = (1.0 / 0.0); 
        double num3 = 4; 
  
        // Returns Euler's number e raised to the given power 
        double expValue = StrictMath.exp(num1); 
        System.out.println("The exp value of "+ 
                         num1+" = " + expValue); 
  
        expValue = StrictMath.exp(num2); 
        System.out.println("The exp value of "+ 
                         num2+" = " + expValue); 
  
        expValue = StrictMath.exp(num3); 
        System.out.println("The exp value of "+ 
                         num3+" = " + expValue);    } 
}
輸出:
The exp value of 0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 4.0 = 54.598150033144236

程序2:

// Java praogram to illustrate the 
// java.lang.StrictMath.exp() 
import java.lang.*; 
  
public class Geeks { 
  
    public static void main(String[] args) 
    { 
  
        double num1 = -0.0, num2 = (1.0 / 0.0); 
        double num3 = 14; 
  
        // Returns Euler's number e raised to the given power 
        double expValue = StrictMath.exp(num1); 
        System.out.println("The exp value of "+ 
                         num1+" = " + expValue); 
  
        expValue = StrictMath.exp(num2); 
        System.out.println("The exp value of "+ 
                         num2+" = " + expValue); 
  
        expValue = StrictMath.exp(num3); 
        System.out.println("The exp value of "+ 
                         num3+" = " + expValue); 
    } 
}
輸出:
The exp value of -0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 14.0 = 1202604.2841647768


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注:本文由純淨天空篩選整理自ankita_chowrasia大神的英文原創作品 StrictMath exp() Method in Java。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。