Permutation.full_cyclic_form():full_cyclic_form()是一個sympy Python庫函數,通過包含單例以循環形式返回置換。
用法:
sympy.combinatorics.permutations.Permutation.full_cyclic_form()
返回:
循環形式的排列
代碼1:full_cyclic_form()示例
# Python code explaining
# SymPy.Permutation.full_cyclic_form()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.full_cyclic_form() method
# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])
b = Permutation([3, 1, 2, 5, 4, 0])
print ("Permutation a - full_cyclic_form form : ", a.full_cyclic_form)
print ("Permutation b - full_cyclic_form form : ", b.full_cyclic_form)
輸出:
Permutation a – full_cyclic_form form : [[0, 2, 3, 1], [4, 5]]
Permutation b – full_cyclic_form form : [[0, 3, 5], [1], [2], [4]]
代碼2:full_cyclic_form()示例– 2D排列
# Python code explaining
# SymPy.Permutation.full_cyclic_form()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.full_cyclic_form() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - full_cyclic_form form : ", a.full_cyclic_form)
輸出:
Permutation a – full_cyclic_form form : [[0, 3, 5, 6, 1, 2, 4]]
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