Permutation.from_sequence():from_sequence()是一個sympy Python庫函數,它返回從“ i”的排序元素中獲取“ i”所需的排列。如果需要任何自定義字符串,也可以將“鍵”作為參數傳遞。
用法:
sympy.combinatorics.permutations.Permutation.from_sequence()
返回:
返回所需的排列
從“ i”的排序元素中獲取“ i”
代碼1:from_sequence()示例
# Python code explaining
# SymPy.from_sequence()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.from_sequence() method
# creating vectors
a = [1, 0, 0, 0]
b = [6, 5, 4, 3, 0, 0 ]
# inversion forms
print ("vector a - from_sequence form : \n", Permutation.from_sequence(a))
print ("vector b - from_sequence form : \n", Permutation.from_sequence(b))
輸出:
vector a – from_sequence form :
Permutation([3, 0, 1, 2])vector b – from_sequence form :
Permutation([5, 4, 3, 2, 0, 1])
代碼2:from_sequence()示例–使用字符串和鍵
# Python code explaining
# SymPy.from_sequence()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.from_sequence() method
# creating vector
a = [2, 3, 1, 0]
# inverted vector of a
print ("vector a - from_sequence form : ",
Permutation.from_sequence(a))
# length = 5, so permutation as per that.
print ("\nstring - from_sequence form : ",
Permutation.from_sequence('GEEKS'))
# length = 5, so permutation as per that.
# defining a key
print ("\nstring - from_sequence form : ",
Permutation.from_sequence('GEEKS', key = lambda x: x.lower()))
輸出:
vector a – from_sequence form : Permutation([2, 3, 1, 0])
string – from_sequence form : Permutation([2, 0, 1, 3, 4])
string – from_sequence form : Permutation([2, 0, 1, 3, 4])
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