排列.from_inversion_vector():from_inversion_vector()是一個sympy Python庫函數,它從反轉向量返回排列。
反向量–排列中第ith個元素左側的元素個數>第ith個元素給出了反演向量的第i個元素。
用法:
sympy.combinatorics.permutations.Permutation.from_inversion_vector()
返回:
反演向量的排列
代碼1:from_inversion_vector()示例
# Python code explaining
# SymPy.from_inversion_vector()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.from_inversion_vector() method
# creating vectors
a = [1, 0, 0, 0]
b = [6, 5, 4, 3, 0, 0 ]
# inversion forms
print ("vector a - from_inversion_vector form : ",
Permutation.from_inversion_vector(a))
print ("vector b - from_inversion_vector form : ",
Permutation.from_inversion_vector(b))
輸出:
vector a – from_inversion_vector form : Permutation([1, 0], size=5)
vector b – from_inversion_vector form : Permutation([6, 5, 4, 3, 0, 1, 2])
代碼2:from_inversion_vector()示例
# Python code explaining
# SymPy.from_inversion_vector()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from
# sympy.combinatorics.permutations.Permutation.from_inversion_vector() method
# creating vector
a = [2, 3, 1, 0]
# inverted vector of a
print ("vector a - from_inversion_vector form : ",
Permutation.from_inversion_vector(a))
輸出:
vector a – from_inversion_vector form : Permutation([2, 4, 1, 0, 3])
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