Python SymPy Permutation.atoms()用法及代碼示例

Permutation.atoms()：atoms()是一個sympy Python庫函數，它返回排列中存在的所有元素。

用法： sympy.combinatorics.permutations.Permutation.atoms()

返回：論證排列的元素。

代碼1：atoms()示例

# Python code explaining 
# SymPy.Permutation.atoms() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.atoms() method  
  
# creating Permutation 
a = Permutation([[2, 0], [3, 1]]) 
  
b = Permutation([1, 3, 5, 4, 2, 0]) 
  
  
print ("Permutation a - atoms form : ", a.atoms()) 
print ("Permutation b - atoms form : ", b.atoms())

輸出：

Permutation a – atoms form : {0, 1, 2, 3}
Permutation b – atoms form : {0, 1, 2, 3, 4, 5}

代碼2：atoms()示例– 2D排列

# Python code explaining 
# SymPy.Permutation.atoms() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.atoms() method  
  
# creating Permutation 
a = Permutation([[2, 4, 0],  
                 [3, 1, 2], 
                 [1, 5, 6]]) 
  
  
print ("Permutation a - atoms form : ", a.atoms())

輸出：

Permutation a – ascents form : [1, 2, 4]

相關用法

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